2m^2=17m-30

Solution for 2m^2=17m-30 equation:

2m^2=17m-30

We move all terms to the left:

2m^2-(17m-30)=0

We get rid of parentheses

2m^2-17m+30=0

a = 2; b = -17; c = +30;
Δ = b2-4ac
Δ = -172-4·2·30
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*2}=\frac{10}{4}
=2+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*2}=\frac{24}{4}
=6
$